3y=y^2+10

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Solution for 3y=y^2+10 equation:


Simplifying
3y = y2 + 10

Reorder the terms:
3y = 10 + y2

Solving
3y = 10 + y2

Solving for variable 'y'.

Reorder the terms:
-10 + 3y + -1y2 = 10 + y2 + -10 + -1y2

Reorder the terms:
-10 + 3y + -1y2 = 10 + -10 + y2 + -1y2

Combine like terms: 10 + -10 = 0
-10 + 3y + -1y2 = 0 + y2 + -1y2
-10 + 3y + -1y2 = y2 + -1y2

Combine like terms: y2 + -1y2 = 0
-10 + 3y + -1y2 = 0

Begin completing the square.  Divide all terms by
-1 the coefficient of the squared term: 

Divide each side by '-1'.
10 + -3y + y2 = 0

Move the constant term to the right:

Add '-10' to each side of the equation.
10 + -3y + -10 + y2 = 0 + -10

Reorder the terms:
10 + -10 + -3y + y2 = 0 + -10

Combine like terms: 10 + -10 = 0
0 + -3y + y2 = 0 + -10
-3y + y2 = 0 + -10

Combine like terms: 0 + -10 = -10
-3y + y2 = -10

The y term is -3y.  Take half its coefficient (-1.5).
Square it (2.25) and add it to both sides.

Add '2.25' to each side of the equation.
-3y + 2.25 + y2 = -10 + 2.25

Reorder the terms:
2.25 + -3y + y2 = -10 + 2.25

Combine like terms: -10 + 2.25 = -7.75
2.25 + -3y + y2 = -7.75

Factor a perfect square on the left side:
(y + -1.5)(y + -1.5) = -7.75

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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